面试题 05.06. 整数转换

参考：

https://leetcode-cn.com/problems/convert-integer-lcci/solution/javazhi-jie-yi-huo-pythonxu-yao-dui-fu-shu-te-shu-/

class Solution:
    def convertInteger(self, A: int, B: int) -> int:
        if A == B:
            return 0
        if A < 0:  # 对于负数，需要将A与全1的32位 与
            A &= 0xffffffff
        if B < 0:
            B &= 0xffffffff
        xor = A ^ B
        count = 0
        while xor != 0:
            xor = xor & (xor - 1)
            count += 1
        return count  # 数 1 的个数

```
public class Solution {
    public int convertInteger(int A, int B) {
        int xor = A ^ B;
        int count = 0;
        while (xor != 0) {
            xor = xor & (xor - 1);
            count += 1;
        }
        return count;
    }
}